What is the volume of a pyramid with slant height 25 feet and square base with edges of 14 feet?

First find the height of the pyramid. Imagine a triangle with hypo 25 ft and base (14/2) ft. The area of the base is 14^2 ft, or 196 ft^2. The height of the pyramid is found using the Pythagorean Theorem:

(14/2) ^2 + h^2 = 25^2, or 25^2 - 7^2 = h^2

This, in turn, is 625-49 = 576 = h^2, so that h = + 24 ft.

Therefore, the volume of this pyramid is A = (1/3) (196 ft^2) (24 ft)

= 1568 ft^3.