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2 March, 09:13

What is the range of the function f (x) = 3x2 + 6x - 8?

y ≥ - 1

y ≤ - 1

y ≥ - 11

y

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Answers (1)
  1. 2 March, 10:09
    0
    3x^2 + 6x - 8 = 3 (x^2 + 2x - 8/3) = 3 (x^2 + 2x + 1 - 8/3 - 1) = 3 (x + 1) ^2 + 3 (-8/3 - 1) = 3 (x + 1) - 11

    Vertex = (-1, - 11)

    Range = y
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