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11 February, 07:33

A 3 kg block is pulled with a force of 45 b along with frictionless horizontal surface at an angle of 30 degrees what is the horizontal force acting on the block

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  1. 11 February, 09:09
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    Fₐ ≈ 38.97 N

    Step-by-step explanation:

    The illustration forms a right angle triangle with the horizontal side been the side of horizontal force.

    The horizontal component of the applied force can be calculated as follows

    Force applied on the block = 45 N

    The force on the horizontal is the force of acceleration use to pull the block.

    Fₐ = 45 N cos 30°

    The formula is gotten by using the cosine ratio of the right angle triangle formed.

    Recall

    cos 30° = adjacent/hypotenuse

    Fₐ = 45 N cos 30°

    Fₐ = 45 * cos 30°

    Fₐ = 45 * 0.86602540378

    Fₐ = 38.9711431703

    Fₐ ≈ 38.97 N
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