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5 February, 02:01

4z+27+5x=14y

If x, y and z each represent a different digit from 0 - 9 what is the value of (x) (y) (z)

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  1. 5 February, 03:46
    0
    In order for the equation to work, x must be odd. Trying different values of x, we find 5 solutions:

    (x, y, z) = (1, 4, 6), (3, 5, 7), (5, 6, 8), (7, 5, 2), (9, 6, 3)

    Then the product xyz could be any of 24, 105, 240, 70, or 162.
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