For the function f (x) = ax^3 - ax^2 - ax-5, f (1) = 3 what is the value of f (-2) ?

Question

Mathematics

Zoe Riggs

29 December, 20:15

For the function f (x) = ax^3 - ax^2 - ax-5, f (1) = 3 what is the value of f (-2) ?

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Answers (1)

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Litzy Webb · Answer 1

So, f (1) = 3;

a - a - a - 5 = 3;

- a - 5 = 3;

-a = 5 + 3;

-a = 8;

a = - 8;

f (x) = (-8) x^3 - (-8) x^2 + 8x - 5;

f (-2) = (-8) (-2) ^3 - (-8) (-2) ^2 + 8·2 - 5 = + 64 - 32 + 16 - 5 = 43;