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27 December, 20:15

What is 2 (log3 (8) + log3 (z)) - log3 (3^4 - 7^2) written as a simple logarithm?

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Answers (2)
  1. 27 December, 22:03
    0
    log₃ (2z²)

    Step-by-step explanation:

    2 (log₃8 + log₃z) - log₃ (3⁴ - 7²)

    = 2[log₃ (2³) + log₃z] - log₃ (81 - 49)

    = 2 (3log₃2 + log₃z) - log₃ (32)

    = 6log₃2 + 2log₃z - log₃ (2⁵)

    = 6log₃2 + 2log₃z - 5log₃2

    = log₃2 + log₃ (z²)

    = log₃ (2z²)
  2. 27 December, 22:57
    0
    the answer is

    B on edge
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