Where is the location of the vertex of the parabola on a coordinate grid?

y=x^2+2x-3

above the x-axis

below the x-axis

on the x-asxis

on the y-axis

below the x-axis

Step-by-step explanation:

y=x^2+2x-3

the vertex is located on the axis of symmetry

h

to find h ax^2 + bx+c

h = - b/2a = - 2/2 (1) = - 1

the x coordinate of the vertex is - 1

to find the y coordinate, substitute into the equation

y = (-1) ^2 + 2 (-1) - 3

= 1-2-3

= - 4

(-1,-4)

the vertex is below the x axis