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7 August, 18:46

1. If P (x) = x^4 + ax^2 + bx-6 with P (4) = 6 and P (2) = 0, find the values of a and b.

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  1. 7 August, 19:05
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    a = - 4, b = - 3

    Step-by-step explanation:

    P (2) = 0

    = 4a + 2b = - 10

    P (4) = 6

    = 16a + 4b = - 52

    16a + 4b = - 52 - 8a + 4b = - 20

    = 8a = - 32

    a = - 4

    b = - 3
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