Find the root (s) of f (x) = (x - 6) 2 (x + 2) 2.

-6 with multiplicity 1

-6 with multiplicity 2

6 with multiplicity 1

6 with multiplicity 2

-2 with multiplicity 1

-2 with multiplicity 2

2 with multiplicity 1

2 with multiplicity 2

6 with multiplicity 2

-2 with multiplicity 2

Step-by-step explanation:

We have given that find the roots of:

f (x) = (x - 6) ² (x + 2) ²

Note that the polynomials are already in the factored form. So we will only make it equal to zero

(x-6) ² = 0

The square tells us that the root repeat twice

Move - 6 to the R. H. S

Then,

x=6, 6

(x+2) ²=0

Move 2 to the R. H. S

Then,

x = - 2, - 2

Therefore the correct options are:

6 with multiplicity 2

-2 with multiplicity 2 ...

4 and 6

~6 with multiplicity 2

~ - 2 with multiplicity 2