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5 December, 18:43

What is the correct factorization of 6 (x - 2) + y (x - 2) ?

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Answers (2)
  1. 5 December, 20:12
    0
    (x - 2) (6 + y)
  2. 5 December, 21:00
    0
    (x - 2) (6 + y)

    Step-by-step explanation:

    Given

    6 (x - 2) + y (x - 2) ← factor out (x - 2) from each term

    = (x - 2) (6 + y) ← in factored form
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