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19 March, 15:26

Y^2-y=2 how do you solve?

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  1. 19 March, 16:32
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    y² - y = 2

    y² - y - 2 = 2 - 2

    y² - y - 2 = 0

    y = - (-1) + / - √ ((-1) ² - 4 (1) (-2))

    2 (1)

    y = 1 + / - √ (1 + 8)

    2

    y = 1 + / - √ (9)

    2

    y = 1 + / - 3

    2

    y = 1 + 3 or y = 1 - 3

    2 2

    y = 4 y = - 2

    2 2

    y = 2 y = - 1
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