If f (x) = x/3-2then find g (x) = 3x^2+2x-6

Step-by-step explanation:

Answer:

(f+g) (x) = 3x^2+/frac{7}{3}x-8

Step-by-step explanation:

The given functions are:

f (x) = / frac{x}{3}-2 and g (x) = 3x^2+2x-6

Now, (f+g) (x) = f (x) + g (x)

therefore, (f+g) (x) = / frac{x}{3}-2+3x^2+2x-6

=3x^2+2x+/frac{x}{3}-8

=/frac{9x^2+6x+x-24}{3}

=/frac{9x^2+7x-24}{3}

=3x^2+/frac{7}{3}x-8

Thus, (f+g) (x) = 3x^2+/frac{7}{3}x-8