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17 September, 14:32

Question 9 Unsaved For all x, (2x+3) ^2=? Question 9 options: 4x^2+9 4x^2+6x+9 4x^2+6 4x^2+12x+9

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  1. 17 September, 16:18
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    It's 4x^2+12x+9 because (2x+3) ^2 Is just another way of writing

    (2x+3) (2x+3) and all you do is distribute which gives you 4x^2+6x+6x+9 which can be simplified into 4x^2+12x+9.
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