Ask Question
1 July, 09:52

What is the center and radius of the circle with equation (x - 2) ^2 + (y - 5) ^2 = 100?

center (2, 5); radius = 10

center (2, - 5); radius = 100

center (-5, 2); radius = 10

center (-2, 5); radius = 100

+4
Answers (2)
  1. 1 July, 10:10
    0
    Center = (2,5)

    Radius = 10

    Choice A

    To find this answer, first write the equation

    (x-2) ^2 + (y-5) ^2 = 100

    into

    (x-2) ^2 + (y-5) ^2 = 10^2

    Note how the second equation is in the form

    (x-h) ^2 + (y-k) ^2 = r^2

    We see that (h, k) = (2,5) is the center

    and r = 10 is the radius
  2. 1 July, 13:34
    0
    A) Center (2, 5); radius = 10.

    Step-by-step explanation:

    Given : (x - 2) ² + (y - 5) ² = 100.

    To find : What is the center and radius of the circle with equation.

    Solution : We have given (x - 2) ² + (y - 5) ² = 100.

    Standard form of circle : (x - h) ² + (y - k) ² = r².

    Where, center = (h, k), r = radius.

    On comparing (x - 2) ² + (y - 5) ² = 100 with (x - h) ² + (y - k) ² = r².

    We can write (x - 2) ² + (y - 5) ² = 10².

    h = 2, k = 5, r = 10.

    Center (2, 5); radius = 10.

    Therefore, A) Center (2, 5); radius = 10.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “What is the center and radius of the circle with equation (x - 2) ^2 + (y - 5) ^2 = 100? center (2, 5); radius = 10 center (2, - 5); radius ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers