How do I find the slope-intercept of 3x+3y=12 and 2x=3y-9?

For the first one your going to use a table of x on one side and y on another and put 0 for x and y for 1 then subsitute it into the question like so. 3 (0) + 3y=12 then 3 times 0 is 0, next divide 3 to each side so it's 12:3 then you'll get 4 so y=4 the do the same for x. then graph it so take a pint from the question then do rise over run. for example (2,4) graph that then go up by 3 then over 4.

the next question get the question in slope intercept form y=mx+b so take 3y away from each side then take 2x from each side so it should look like - 3y=-2x - 9 then graph it cause - 2 is slope so the y Inter. is 9 then that should be it.

put y on one side and solve for y

y=mx+b