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26 November, 12:40

The length and width of a rectangular patio are, (x + 8) feet and (x + 6) feet,

respectively. If the area of the patio is 160 square feet, what are the dimensions

of the patio?

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Answers (2)
  1. 26 November, 13:02
    0
    Answer: x = √73

    Step-by-step explanation: Ration = (x+8) : (x+6)

    Let x be the length and breadth

    Length = (x+8) x

    breadth = (x+6) x

    Area = 160 feet sq.

    = (x+8) x = x² + 8x = length

    (x+6) x = x²+6x = breadth

    →x²+8x+x²+6x = 160

    2x²+14 = 160

    2x² = 146

    x² = 73

    x = √73
  2. 26 November, 14:41
    0
    Area = length x width

    160 = (x+8) (x+6)

    160 = x2 + 14x + 48

    x2 + 14x - 112 = 0 and solve with the quadratic formula and get x=-7+sqrt (161)
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