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28 June, 07:59

A bag contains 6 red balls numbered 1, 2, 4, 5, 8, 9 and 4 white balls numbered 3, 6, 7, 10,

at random, what is the probability the ball is

8, 9 and 4 white balls numbered 3, 6, 7, 10. If a ball is drawn

a. red or odd-numbered?

b. white or even-numbered

+2
Answers (1)
  1. 28 June, 11:57
    0
    60%

    a. 80%

    b. 70%

    Step-by-step explanation:

    In this case we are first asked for the probability that when drawing a ball at random it is 8, 9 and 4 white balls numbered 3, 6, 7, 10, that is 6 balls. We know that there are a total of 10 balls since they are 6 red and 4 white, 6 + 4 = 10.

    Therefore the probability is:

    6/10 = 0.6

    that is to say that the probability that it is one of these balls is 60%

    to. that is red or odd,

    red are 1, 2, 4, 5, 8, 9 and in addition to that, in white there is one with 3 and with 7 that are odd, making them 8 balls, therefore:

    8/10 = 0.8

    In other words, the probability is 80%

    b. white or even,

    the white ones are 3, 6, 7, 10 and in the red ones the 2, 4 and 8 are even, that is to say that they are 7 balls, which means that:

    the probability is:

    7/10 = 0.7

    The probability is 70%
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