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30 September, 07:59

The dimensions of a rectangle can be given by x+7 and x+2. If the area of the rectangle is 66 square inches, what are the dimensions of the rectangle?

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  1. 30 September, 10:56
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    to solve for the dimensions (x+7) (x+2) = 66,

    we can first use the foiling method to simplify the left side.

    x^2 + 2x + 7x + 14 = 66

    x^2 + 9x + 14 = 66

    now, subtract 66 from both sides.

    x^2 + 9x - 52 = 0

    now, split this into two parentheses.

    (x + 13) (x - 4)

    since the root of - 13 would give you negative values, x=4. This means that the dimensions of the rectangle are 11 and 6.
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