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7 March, 08:01

What is the solution system y=2/3x-2 y=-x+3

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  1. 7 March, 10:28
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    x = 3, y = 0

    Step-by-step explanation:

    Solve the following system:

    {y = (2 x) / 3 - 2 | (equation 1)

    y = 3 - x | (equation 2)

    Express the system in standard form:

    { - (2 x) / 3 + y = - 2 | (equation 1)

    x + y = 3 | (equation 2)

    Swap equation 1 with equation 2:

    {x + y = 3 | (equation 1)

    - (2 x) / 3 + y = - 2 | (equation 2)

    Add 2/3 * (equation 1) to equation 2:

    {x + y = 3 | (equation 1)

    0 x + (5 y) / 3 = 0 | (equation 2)

    Multiply equation 2 by 3/5:

    {x + y = 3 | (equation 1)

    0 x+y = 0 | (equation 2)

    Subtract equation 2 from equation 1:

    {x+0 y = 3 | (equation 1)

    0 x+y = 0 | (equation 2)

    Collect results:

    Answer: {x = 3, y = 0
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