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Mathematics
Cassius Mendoza
7 March, 08:01
What is the solution system y=2/3x-2 y=-x+3
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Hector
7 March, 10:28
0
x = 3, y = 0
Step-by-step explanation:
Solve the following system:
{y = (2 x) / 3 - 2 | (equation 1)
y = 3 - x | (equation 2)
Express the system in standard form:
{ - (2 x) / 3 + y = - 2 | (equation 1)
x + y = 3 | (equation 2)
Swap equation 1 with equation 2:
{x + y = 3 | (equation 1)
- (2 x) / 3 + y = - 2 | (equation 2)
Add 2/3 * (equation 1) to equation 2:
{x + y = 3 | (equation 1)
0 x + (5 y) / 3 = 0 | (equation 2)
Multiply equation 2 by 3/5:
{x + y = 3 | (equation 1)
0 x+y = 0 | (equation 2)
Subtract equation 2 from equation 1:
{x+0 y = 3 | (equation 1)
0 x+y = 0 | (equation 2)
Collect results:
Answer: {x = 3, y = 0
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