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28 February, 15:00

What is the center of the circle with the equation x2 + y2 + 4x-8y+11 = 0?

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  1. 28 February, 17:16
    0
    (-2,4)

    Step-by-step explanation:

    You do this by completing the square for x and y.

    x^2 + 4x + (4/2) ^2 + y^2 - 8x + (-8/2) ^2 = - 11 + 4 + 16

    (x + 2) ^2 + (y - 4) ^2 = 9

    The center should be (-2,4)
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