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11 November, 05:29

A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg football player continues moving at a velocity of 2.00 m/s after the collision. What is the velocity of the 85.0 kg football player after the collision?

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  1. 11 November, 07:49
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    -1.13 m/s

    Step-by-step explanation:

    Parameters given:

    Mass of first footballer, M = 92 kg

    Initial velocity of first footballer, U = 6.5 m/s (taking North to be the + ve y axis)

    Mass of second footballer, m = 85 kg

    Initial velocity of second footballer, u = - 6.0 m/s (taking South to be the - ve y axis)

    Final velocity of first footballer, V = 2.0 m/s

    We need to find the final velocity of the second football (v)

    Applying the principle of conservation of momentum, we have that, in a system:

    Total Initial Momentum = Total Final Momentum

    (M * U) + (m * u) = (M * V) + (m * v)

    (92 * 6.5) + (85 * - 6) = (92 * 2) + (85 * v)

    598 - 510 = 184 + 85v

    88 = 184 + 85v

    88 - 184 = 85v

    -96 = 85v

    => v = - 96 / 85

    v = - 1.13 m/s

    The final velocity of the 85 kg player is - 1.13 m/s i. e 1.13 m/s South
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