Solve 49x^2+64=0 by using square roots

x = ±i8/7

Step-by-step explanation:

49x^2 + 64 = 0

Subtract 64 from each side

49x^2 + 64-64 = 0-64

49x^2 = - 64

Divide by 49

49x^2/49 = -64 / 49

x^2 = - 64 / 49

Take the square root of each side

sqrt (x^2) = ±sqrt ( - 64 / 49)

x = ±sqrt ( - 64 / 49)

We know sqrt (ab/c) = sqrt (a) sqrt (b) / sqrt (c)

x = ±sqrt ( - 1) sqrt (64) / (49)

We know that the sqrt (-1) = i

x = ±i8/7