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24 September, 10:37

Find the dimensions of a rectangle with perimeter 84 m whose area is as large as possible. (If both values are the same number, enter it into both blanks.) m (smaller value) m (larger value)

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  1. 24 September, 12:18
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    m=21 and n=21

    Step-by-step explanation:

    In order to maximize the area of the rectangle, you want the two side lengths to be as equal to each other as possible.

    In this case, we get that 2m+2n=84, so m+n=42. In our case, m and n can equal each other, so that gives us the maximum area of 441

    Proof that this works:

    If we had other dimensions, like m=20 and n=22, the area would be 440, slightly less than 442. If m=19 and n=23, the area becomes 437, which is even further off from 441.
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