Describe the nature of the roots for this equation 2x^2+5x-7=0

x = - 7/2 and x = 1

So, there are 2 roots of this equation.

And the roots are real numbers.

Step-by-step explanation:

We need to describe the nature of roots for this equation

2x^2+5x-7=0

2x^2-2x+7x-7=0

2x (x-1) + 7 (x-1) = 0

(2x+7) (x-1) = 0

2x+7=0, x-1=0

2x=-7, x = 1

x = - 7/2 and x = 1

So, there are 2 roots of this equation.

And the roots are real numbers.