What are the zeros of f (x) = x2 + x - 12?

O A. x = - 4 and x = 3

O B. x=-6 and x = 2

O c. x=-2 and x = 6

D. x = - 3 and x = 4

Answer:the answer is D

f

(

x

)

has zeros at

-

3

and

4

Explanation:

f

(

x

)

=

x

2

-

x

-

12

x

-

2

=

(

x

+

3

)

(

x

-

4

)

x

-

2

∴

f

(

x

)

=

0

→

(

x

+

3

)

(

x

-

4

)

x

-

2

=

0

Hence the zeros of

f

(

x

)

occur when

(

x

+

3

)

(

x

-

4

)

=

0

Note:

f

(

x

)

is undefined at

x

=

2

∴

f

(

x

)

=

0

at

x

=

-

3

and

x

=

4

This can be seen from the grapg of

f

(

x

)

below:

graph{ ((x+3) (x-4)) / (x-2) [-18.01, 18.04, - 9.01, 8.99]}

Step-by-step explanation:

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