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24 April, 01:21

Prove that for a, b, c E ℤ, if a ❘ (ab + c), then a I c.

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  1. 24 April, 04:04
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    True.

    Step-by-step explanation:

    Let a, b, c integers and a | (ab+c), that is to say that there exist a integer k such that ab+c = ka. Then:

    ab+c = ka

    c = ka-ab

    c = a (k-b). So, c is a multiple of a, that is a | c.
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