1 December, 17:28

The goals against average (A) for a professional hockey goalie is determined using the formula A=60 (g/2). In the formula, g represents the number of goals scored against the goalie and t represents the time played, in minutes. Which is an equivalent equation solved for g?A) At/60=gB) A/60t=gC) 60A/t=gD) 60At=g

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Answers (2)
1. 1 December, 19:01
0
g=at/60
2. 1 December, 19:13
0
g = At/60

Step-by-step explanation:

Given:

A = 60 (g/t)

60 (g/2) is a mistake in the question which the question has corrected in the comments)

A is the average for a professional hockey goalie.

g is the number of goals scored against the goalie.

t represents the time played in minutes.

Finding 'g':

A = 60 (g/t)

can be written as A = (60*g) / t

Multiplying by 't' on both sides:

At = (60*g) * t/t

At = 60*g

Dividing by '60' on both sides:

At/60 = 60*g/60

At/60 = g

⇒ g = At/60
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