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9 October, 06:59

Use the process of completing the square and/or factoring to find the zeros and axis of symmetry for the graph of the function.

f (x) = x^2 - 14x - 72

A.

zeros: x = - 4 and x = 18;

axis of symmetry: x = 7

B.

zeros: x = - 18 and x = 4;

axis of symmetry: x = - 7

C.

zeros: x = - 9 and x = - 8;

axis of symmetry: x = - 7

D.

zeros: x = 9 and x = 8;

axis of symmetry: x = 7

EDIT: The answer is here.

The axis of symmetry is 7.

The roots were 18 & - 4

+2
Answers (2)
  1. 9 October, 08:00
    0
    A)

    zeros: x = - 4 and x = 18;

    axis of symmetry: x = 7

    Step-by-step explanation:

    Given the equation of function

    f (x) = x² - 14x - 72

    here a = 2

    b = - 14

    c = - 72

    by using quadratic equation

    x = (-b ± √b² - 4ac) / 2a

    x1 = 14 + √14² + 4 (1) (72) / 2

    = 18

    and

    x2 = 14 - √14² + 4 (1) (72) / 2

    = - 4

    For symmetry of axis

    It is a vertical line with the equation of x = - b/2a

    x = - (-14) / 2 (1)

    x = 7
  2. 9 October, 08:07
    0
    I believe it is D.
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