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11 February, 01:54

Given: △ABC is a right triangle There are 3 shaded squares with sides a, b, and c, respectively. a, b, and c are also the lengths of the sides of the right triangle, such that the area of the square with side a is a2 and the area of the square with side b is b2 and the area of the square with side c is c2. Prove: a2 + b2 = c2 (Pythagorean Theorem) Proving which of the following will prove the Pythagorean Theorem? A When you subtract the area of the smallest square from the medium square the difference equals the area of the largest square. B The sides of a right triangle are also the sides of squares. C m∠A+m∠B=m∠C D The area of the two smaller squares will add up to the area of the largest square.

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  1. 11 February, 02:59
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    a2 + b2 = c2 because a + b = c
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