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13 February, 04:22

What is the solution to the system of equations below?

2 x minus y = 10 and y = negative one-half x + 5

(6, 2)

(6, - 2)

(-6, - 22)

(-6, 8)

+4
Answers (2)
  1. 13 February, 06:33
    0
    The correct one is A

    Step-by-step explanation:

    2x-y=10

    y=1/2 * x+5

    Now you substitute the value of y into the first equation.

    2x - (1/2 * x+5) = 10

    Solving this equation for x you get that x=6

    Now substitute the value of x any of these two equations, doesn't matter. Let's say we do with the first one.

    2*6-y=10

    12-y=10

    -y=10-12

    -y = - 2

    y=2

    And so you've got the first one which is, (x, y) = (6,2)
  2. 13 February, 06:45
    0
    the correct answer is a
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