F (x) = 3x + 1 and f^-1=x-1/3

then f (2)

Input:

{F (x) = 3 x + 1, 1/f = x - 1/3 f (2) }

Result:

{F (x) = 3 x + 1, 1/f = x - f (2) / 3}

Alternate forms:

{3 x + 1 = F (x), 3 x = f (2) + 3/f}

{F (x) = 3 x + 1, f (2) = 3 x - 3/f}

{F (x) = 3 x + 1, 1/f = 1/3 (3 x - f (2)) }

Alternate form assuming f and x are positive:

{3 x + 1 = F (x), 3 f x = f (2) f + 3}