Let f (x) = x^7-4e^x

A) f' (-1)

b) f'' (-1)

Step-by-step explanation:

Let f (x) = x^7 - 4e^x.

Then f ' (x) = 7x^6 - 4e^x, and

f " (x) = 42x^5 - 4e^x, and so:

f ' (-1) = 7 (-1) ^6 - 4e^ (-1) = 7 + 4/e

and

f " (x) = 42 (-1) ^5 - 4e^ (-1) = - 42 + 4/e