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2 May, 18:47

Let f (x) = x^7-4e^x

A) f' (-1)

b) f'' (-1)

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Answers (1)
  1. 2 May, 21:18
    0
    Step-by-step explanation:

    Let f (x) = x^7 - 4e^x.

    Then f ' (x) = 7x^6 - 4e^x, and

    f " (x) = 42x^5 - 4e^x, and so:

    f ' (-1) = 7 (-1) ^6 - 4e^ (-1) = 7 + 4/e

    and

    f " (x) = 42 (-1) ^5 - 4e^ (-1) = - 42 + 4/e
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