The sum of all digits in the numbers 44, 45, and 46 is 27 because (4+4) + (4+5) + (4+6) = 27. Find the sum of digits in the first 25 counting numbers: 1, 2, 3, ..., 25.

The sum of the digits in the first 25 counting numbers, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, and 25 is 127

Step-by-step explanation:

The question regards the addition of single digits in numbers and asks of the sum of the digits in the first 25 numbers as follows;

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 0 + 1 + 1 + 1 + 2 + 1 + 3 + 1 + 4 + 1 + 5 + 1 + 6 + 1 + 7 + 1 + 8 + 1 + 9 + 2 + 0 + 2 + 1 + 2 + 2 + 2 + 3 + 2 + 4 + 2 + 5 = 127

The sum of the digits in the first 25 counting numbers, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, and 25 = 127.