If the sum of five consecutive odd integers is 265, what is the smallest of the five integers?

The smallest integer = 49

Step-by-step explanation:

It is given that, the sum of five consecutive odd integers is 265

To find the smallest integer

Let 'x' be the smallest odd integer, the other integers are,

(x + 2), (x + 4), (x + 6), and (x + 8)

x + x + 2 + x + 4 + x + 6 + x + 8 = 265

5x + 20 = 265

5x = 245

x = 245/5 = 49

Therefore the smallest integer = 49