A rectangle has an area of K + 19k + 60 square inches. If the value of k and the dimensions of the rectangle are all natural

numbers, which statement about the rectangle could be true?

The length of the rectangle is k-5 inches.

The width of the rectangle is k + 4 inches.

The length of the rectangle is k-20 inches.

The width of the rectangle is k + 10 inches.

Thats correct! The answer is B. (2nd option.) I took edge.

Step-by-step explanation:

By definition, the area of a rectangle is given by:

A = w * lA=w∗l

Where,

w: width of the rectangle

l: length of the rectangle

We then have the following expression for the area:

A = k ^ 2 + 19k + 60A=k

2

+19k+60

What we must do is factorize the expression following the following steps:

1) Find two numbers that are equal to 19

2) Find two multiplied numbers equal to 60

We have then:

A = (k + 15) (k + 4) A = (k+15) (k+4)

Therefore, the width of the rectangle is:

w = (k + 4) w = (k+4)