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31 May, 08:20

Find the equation of a parabola with vertex at the origin and focus (0, - 32).

y^2 = - 128x

x^2 = - 32y

x^2 = 128y

x^2=-128y

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  1. 31 May, 10:46
    0
    x^2 = - 128y

    Step-by-step explanation:

    The general formula for this type of parabola is x^2 = 4ay where a is the y coordinate of the focus. So 4a = 4*-32 = 1-28.

    So the answer is x^2 = - 128y
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