Ask Question
28 December, 01:28

The net below can be folded to form a square pyramid.

A square pyramid. The square base has side lengths of 9 inches. The triangular sides have a height of 6.1 inches and side length of 7.6 inches.

What is the surface area of the pyramid?

190.8 square inches

217.8 square inches

300.6 square inches

354.6 square inches

+4
Answers (2)
  1. 28 December, 02:27
    0
    190.8 square inches

    Step-by-step explanation:

    The area of one of its triangular sides is given by A = bh/2 were b = base = 9 inches and h = perpendicular height = 6.1 inches.

    A = bh/2. Since we have 4 triangular sides, the total area of its sides A₁ = 4A = 4bh/2 = 2bh = 2 * 9 * 6.1 = 109.8 square inches.

    The area of is base is the area of a square = 9² = 81 square inches.

    So te total surface area is 109.8 square inches + 81 square inches = 190.8 square inches
  2. 28 December, 04:50
    0
    190.8
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “The net below can be folded to form a square pyramid. A square pyramid. The square base has side lengths of 9 inches. The triangular sides ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers