2x^2-5x-3=0 what values of x make this equation true?

The values of x are - 1/2 and 3

Step-by-step explanation:

∵ 2x² - 5x - 3 = 0

By using factorization

(2x + 1) (x - 3) = 0

2x + 1 = 0 ⇒ 2x = - 1 ⇒ - 1/2

x - 3 = 0 ⇒ x = 3

∴ The values of x are - 1/2 and 3

x = - ½ and x = 3

Step-by-step explanation:

2x² - 5x - 3 = 0

Rewrite - 5x as - 6x + x

2x² - 6x + x - 3 = 0

Factor out 2x from the first pair and 1 from the second pair

2x (x - 3) + 1 (x - 3) = o

Factor out (x - 3)

(2x + 1) (x - 3) = 0

Apply the Zero Product property

2x + 1 = 0 x - 3 = 0

Solve each equation

2x + 1 = 0 x - 3 = 0

2x = - 1 x = 3

x = - ½

The equation is true when x = - ½ and when x = 3.