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27 November, 21:04

Which expression is the completely factored form of x6-64y3?

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  1. 27 November, 21:39
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    (x^2 - 4y) (x^4 + 4x^2y + 16y^2)

    Step-by-step explanation:

    x^6-64y^3

    - using the identity a^3 - b^3 = (a - b) (a^2 + ab + b^2) with a = x^2 and b = 4y we have:-

    (x^2 - 4y) (x^4 + 4x^2y + 16y^2)
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