rebecca has 25 coins, all nickels and dimes. The total value of the coins is $3.60. How many of each type of coin did rebecca have?

Error in given values.

Step-by-step explanation:

Let number nickel coins = x

Let number dime coins = y

Given that total number of coins is 25 so that means

x+y=25

or x=25-y ... (i)

We know that 1 nickel = $0.05

then value of x nickels = 0.05x

We know that 1 dime = $0.10

then value of y dimes = 0.10y

Then total value of both type coins will be 0.05x+0.10y

Given total value is $3.60

So we get

0.05x+0.10y=3.60.

multiply both side by 100 to remove decimals

5x+10y=360

divide both sides by 5

x+2y=72 ... (ii)

now we just need to solve both equations:

plug (i) into (ii)

x+2y=72

25-y+2y=72

25+y=72

y=47

we are getting 47 coins of dimes.

But we have been given that there are only 25 coins which is not possible.

So there must be some misprinting in the question.