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28 June, 17:05

On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0.25, negative 6), and goes through (2, 0). Which statements about the graph of the function f (x) = 2x2 - x - 6 are true? Select two options. The domain of the function is the set of all values x such that x is greater than or equal to one-quarter. The range of the function is all real numbers. The vertex of the function is (one-quarter, negative 6 and one-eighth). The function has two x-intercepts. The function is increasing over the interval (negative 6 and one-eighth, ∞).

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  1. 28 June, 19:30
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    The function has two x-intercepts.

    The vertex of the function is (one-quarter, negative 6 and one-eighth).

    Step-by-step explanation:

    Given that the vertex is located at (0.25, - 6) and the parabola opens up, the function has two x-intercepts.

    f (x) = 2x² - x - 6 has the following coefficients:

    a = 2

    b = - 1

    c = - 6

    x-coordinate of the vertex is:

    x = - b / (2a)

    x = 1 / (2*2) = 1/4

    y-coordinate of the vertex is:

    f (1/4) = 2 (1/4) ² - 1/4 - 6 = - 6 1/8
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