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29 January, 09:43

Kobe Bryant is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 83/%83% of the time.

What is the probability of Kobe Bryant making all of his next 6 free throw attempts?

Choose 1 answer:

a) (1-0.83) ^6

b) 0.83^6

c) 6⋅0.83

d) 6⋅ (1-0.83)

+1
Answers (1)
  1. 29 January, 11:39
    0
    b) 0.83^6

    probability of Kobe Bryant making all of his next 6 free throw attempts

    =probability of Kobe Bryant making first free throw attempts x

    probability of Kobe Bryant making second free throw attempts x

    probability of Kobe Bryant making third free throw attempts x

    probability of Kobe Bryant making fourth free throw attempts x

    probability of Kobe Bryant making fifth free throw attempts x

    probability of Kobe Bryant making sixth free throw attempts

    = P (make 1) x P (make 2nd) x P (make 3rd) x P (make 4th) x P (make 5th) x P (make 6th) = 0.83^6
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