A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.

. The ball's height h (in feet) after t seconds is given by the following.

h = 160 - 12t - 16t^2

How long after the ball is thrown does it hit the ground?

Round your answer (s) to the nearest hundredth.

Question

Mathematics

Hubby

9 June, 07:57

A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.

. The ball's height h (in feet) after t seconds is given by the following.

h = 160 - 12t - 16t^2

How long after the ball is thrown does it hit the ground?

Round your answer (s) to the nearest hundredth.

+2

Answers (1)

Know the Answer?

Ellen Briggs · Answer 1

Step-by-step explanation:

Solve the quadratic equations for h = 0

Quadratic formula:

(12 + - sqrt (144-4 (-16) (160))) / 32

(12 + - sqrt (10384)) / 32

t = - 2.81 (disregard this because a negative doesn't make since in this context)

t=3.56

A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.. The ball's height h (in feet) after t seconds is given by the following.h = 160 - 12t - 16t^2How long after the ball is thrown does it hit the ground?Round your answer (s) to the nearest hundredth.

A ball is thrown from a height of 160 feet with an initial downward velocity of 12 ft/s.

. The ball's height h (in feet) after t seconds is given by the following.

h = 160 - 12t - 16t^2

How long after the ball is thrown does it hit the ground?

Round your answer (s) to the nearest hundredth.