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30 July, 01:07

The sides of a triangle have lengths of x, x + 4, and 20. If the longest side is 20, which of the following values of x would make the triangle obtuse?

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  1. 30 July, 03:54
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    12
    Step-by-step explanation:

    if c^2 > a^2 + b^2

    then the triangle is obtuse

    since 20 is the longest side

    20^2 > x^2 + (x+4) ^2

    simplify

    400 > x^2 + (x+4) (x+4)

    FOIL

    400 > (x^2) + (x^2 + 4x+4x+16)

    combine like terms

    400 > (2x^2 + 8x+16)

    divide by 2

    400/2 > 2x^2 / 2 + 8x/2 + 16/2

    200 > x^2 + 4x + 8

    subtract 200 from each side

    0> x^2 + 4x + 8-200

    0> x^2 + 4x-192

    Factor

    0 > (x-12) (x+16)

    using the zero product property

    0> x-12 0 > x+16

    12>x - 16>x

    x must be greater than 12

    we know the longest side is 20

    x+4 < 20

    subtract 4

    x< 16

    x>12 and x < 16

    12
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