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Mathematics
Kamila Preston
11 July, 10:33
Find the vertex of y=x^2+6x-16
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Andrew
11 July, 13:47
0
(-3,-25)
Step-by-step explanation:
x^2+6x-16
= (x^2+6x+9) - 16-9
= (x+3) ^2-25
When a quadratic is written in the form y = a (x-h) ^2 + k, the vertex is (h, k).
Vertex = (-3,-25)
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