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14 February, 05:31

The volume V of an ideal gas varies directly with the temperature T and inversely with the

pressure P. A cylinder contains oxygen at a temperature of 320 degrees Kelvin and a pressure of

25 atmospheres in a volume of 120 liters. Find the pressure if the volume is decreased to 110

liters and the temperature is increased to 335 degrees Kelvin.

Hint: Look at the equation V = k * Then use the initial values to solve for k. Then plug in the

values you know for the second set of values and solve for your unknown.

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Answers (1)
  1. 14 February, 08:51
    0
    Pressure=22.55 atmospheres

    Step-by-step explanation:

    Let

    V=volume of the ideal gas

    P=pressure

    T=temperature

    Volume varies directly with temperature and inversely with pressure

    V=kT/P

    t=320°K

    P=25 atmospheres

    V=120 liters

    V=kT/P

    120=k*320/25

    120=320k/25

    120*25=320k

    3000=320k

    k=300/320

    =9.375

    k=9.375

    V=110 liters

    p=?

    t=335°K

    V=kT/P

    110=9.375*335/p

    110=3,140.625/p

    110p=3,140.625

    P=3,140.625/110

    =28.55

    P=22.55 atmospheres
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