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Mira Short
31 August, 08:51
What is the standard form of (x+5) (x+5)
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Flakey
31 August, 10:22
0
x² + 10x + 25
Step-by-step explanation:
Given
(x + 5) (x + 5)
Each term in the second factor is multiplied by each term in the first factor, that is
x (x + 5) + 5 (x + 5) ← distribute both parenthesis
= x² + 5x + 5x + 25 ← collect like terms
= x² + 10x + 25 ← in standard form
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