Solve: 18^x^2+4x+4 = 18^9x+18

x = - 2 or + 7

Step-by-step explanation:

We presume you want to solve ...

18^ (x^2 + 4x + 4) = 18^ (9x + 18)

Equate exponents of the same base and put the quadratic in standard form.

x^2 + 4x + 4 = 9x + 18

x^2 - 5x - 14 = 0

(x - 7) (x + 2) = 0

Values of x that make these factors zero are 7 and - 2.

The solutions are x=-2 or x = 7.