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26 August, 00:52

The sum of the first two terms and the sum to infinity of a geometry progression are 48/7 and 7 respectively. Find the values of the common ratio r and the first term when r is positive.

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  1. 26 August, 01:09
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    r = ±1/√7

    a₁ = 7 - √7

    Step-by-step explanation:

    The first term is a₁ and the second term is a₁ r.

    a₁ + a₁ r = 48/7

    The sum of an infinite geometric series is S = a₁ / (1 - r)

    a₁ / (1 - r) = 7

    Start by solving for a₁ in either equation.

    a₁ = 7 (1 - r)

    Substitute into the other equation:

    7 (1 - r) + 7 (1 - r) r = 48/7

    1 - r + (1 - r) r = 48/49

    1 - r + r - r² = 48/49

    1 - r² = 48/49

    r² = 1/49

    r = ±1/√7

    When r is positive, the first term is:

    a₁ = 7 (1 - r)

    a₁ = 7 (1 - 1/√7)

    a₁ = 7 - 7/√7

    a₁ = 7 - √7
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