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28 April, 11:23

Substance A decomposes at a rate proportional to the amount of A present. a) Write an equation relating A to the amount left of an initial amount Upper A 0 after time t. b) It is found that 18 lb of A will reduce to 9 lb in 4.2 hr. After how long will there be only 1 lb left?

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  1. 28 April, 15:08
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    Step-by-step explanation:

    a) The equation relating A to the amount left of an initial amount Upper A 0 after time t is

    A (t) = A0e^ (kt)

    b) It is found that 18 lb of A will reduce to 9 lb in 4.2 hr. It means that

    A0 = 18

    A = 9

    t = 4.2

    Therefore, substituting into the formula, it becomes

    9 = 18e^ (4.2k)

    9/18 = e^ (4.2k)

    0.5 = e^ (4.2k)

    Taking ln of both sides of the equation, it becomes

    Ln0.5 = ln e^ (4.2k)

    - 0.693 = 4.2k

    k = - 0.693/4.2

    k = - 0.165

    The equation becomes

    A (t) = 18e^ ( - 0.165t)

    For A = 1 (1 lb left), then

    1 = 18e^ ( - 0.165t)

    1/18 = e^ ( - 0.165t)

    0.056 = e^ ( - 0.165t)

    Taking ln of both sides, it becomes

    Ln0.056 = ln e^ ( - 0.165t)

    - 2.88 = - 0.165t

    t = - 2.88/-0.165

    t = 17.5 hours

    After 17.5 hours, 1 lb would be left
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